How many milliliters of 0.200 m naoh will be required to titrate 10.5 ml of 0.479 m h2so4

Ans: Volume of NaOH needed = 50.3 ml

Given:

Molarity of NaOH = 0.200 M

Molarity of H2SO4 = 0.479 M

Volume of H2SO4 = 10.5 ml

To determine:

Volume of NaOH required

Explanation:

The titration reaction can be shown as:

2NaOH + H2SO4 → Na2SO4 + 2H2O

Based on the reaction stoichiometry:

2 moles of NaOH reacts with 1 mole of H2SO4

i.e.

moles of NaOH required = 2(moles of H2SO4)

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

d.) circle motion requires a force to give it a centripetal acceleration.