You performed this reaction: Fe2O3 + 3CO --> 2Fe + 3CO2 You used 84.8g of Fe2O3.

What is the theoretical yield of Fe you will make?

The actual yield of the reaction was 54.3g of Fe.

What is the percent yield?

a
The theoretical yield is 338g of Fe. The percent yield is 16.06%
b
The theoretical yield is 14.8g of Fe. The percent yield is 27.31%
c
The theoretical yield is 59.3g of Fe. The percent yield is 91.57%
d
The theoretical yield is 14.8g of Fe. The percent yield is 366%

a is the correct answer

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole