Calcular o número de moléculas contidas em 9,0g de H2O. Massas molares em g/mol: H:1; O:16. Constante de Avogadro = 6,02 . 1023 mol–1

a) 12,04 . 1023 moléculas
b) 3,01 . 1023 moléculas
c) 5,02 . 1023 moléculas
d) 7,02 . 1023 moléculas e) 1,02 . 1023 moléculas

257 grams h2o i think

Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.

27. =3,500,000 x 4,000 = 14,000,000,000