Predicting products, Then balance each equation, and Then write each equation using words for: 1._C (s) +___O2 (g) →
2. ___Ca (s) +___HCl → +
3. ___SiO2 (s) +___ HF (aq) → +
4. ___Fr (s) +___H2 S (g) → ___Fr2 S (s) +___H2 (g)
5. ___K2 CO3 (s) →___K2 O (s) + ___CO2 (g)

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.

It is a product

First adhesives: hide glue.  which is made by boiling raw hides and bones or fish skins and bladders.other first adhesives: asphalt/tar, pitch/plant sap, and even blood.hope that : )

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