How many grams of aluminum is produced when 82.4 grams of aluminum chloride decomposes into chlorine gas and aluminum metal?
2AICI: - 2 Al + 3C12

16.6 g of Al are produced in the reaction of 82.4 g of AlCl₃

Explanation:

Let's see the decomposition reaction:

2AlCl₃ →  2Al  + 3Cl₂

2 moles of aluminum chloride decompose to 2 moles of solid Al and 3 moles of chlorine gas.

We determine the moles of salt:

82.4 g . 1mol/ 133.34g = 0.618 moles

Ratio is 2:2. 2 moles of salt, can produce 2 moles of Al

Then, 0.618 moles of salt must produce 0.618 moles of Al.

Let's convert the moles to mass → 0.618 mol . 26.98g /mol = 16.6 g

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.