Which is the correct complete ionic equation for the reaction of 2HCl(aq) + Zn(s) + H2(g) + ZnCl2(aq)?

a) H+(aq) + CI-(aq) + Zn(s) →
H2(g) + Zn2+(aq) + Cl-(aq)

b) 2H+(aq) + 2C1-(aq) + Zn(s) → H2(g) + Zn2+(aq) + 2Cl-(aq)

c) H+(aq) + Zn(s) → H2(g) + Zn2+(aq)

d) 2H+(aq) + Zn(s) → H2(g) + Zn2+(aq)

b) 2H+(aq) + 2C1-(aq) + Zn(s) → H2(g) + Zn2+(aq) + 2Cl-(aq)

Explanation:

The equation is given as;

2HCl(aq) + Zn(s) + H2(g) + ZnCl2(aq)

In writing an ionic equation, only the aqueous compounds dissociates into ions. This means HCl and ZnCl2 would dissociate to form ions.

This is given as;

2H+  +  2Cl-  + Zn(s) --> H2(g) + Zn2+  + 2Cl-

The correct option is;

b) 2H+(aq) + 2C1-(aq) + Zn(s) → H2(g) + Zn2+(aq) + 2Cl-(aq)

a  solution  is always transparent, light passes through with no scattering from solute particles which are molecule in size. the  solution  is homogeneous and does not settle out. a colloid is intermediate between asolution  and a  suspension. while asuspension  will separate out a colloid will not.

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