How many molecules are in 3.01 g of H2O A. 0.167 molecules
B. 54.18 molecules
C. 1.01x10^23 molecules
D. 6.022x10^23

Option C

Explanation:

No. of Molecules=(Given Weight/Molar weight)*Avagadro No.

Given weight of H2O=3.01g

Molar weight of H2O=18g

On applying the formula, we get:

No. of Molecules=(3.01/18)*6.023*10²³=1.01*10²³

what is the volume occupied by 40 grams of argon gas (ar) at standard conditions? what volume, in liters, is occupied by 1.5 x 1023