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Chemistry, 07.04.2021 21:40 jakeisadog698
You can prepare lcad(II) iodide by reacting lead(II) nitrate with potassium iodide: Pb(NO3)2(aq) + 2Kl(aq) --> Pbl}(s) + 2KNO3(aq) How many grams of Pbl, can you prepare from 44.6 mL of 0.550 M KI?
0.0245 g
5.65 g
4.07 g
11.3 g
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You can prepare lcad(II) iodide by reacting lead(II) nitrate with potassium iodide: Pb(NO3)2(aq) + 2...
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