Indicate the concentration of each ion present in the solution formed by mixing: 3.40g kcl in 75.0 ml of 0.210 m cacl2 solution. assume that the volumes are additive.

To solve this task, we have to use this molar formula : Number of Moles=Mass/Molar Mass.
According to this, we can calculate each :  which is 0,045 moles.
Then use this formula to go on :
№of moles=Concentration(mol/dm3)∗Volume(dm3), and  then , which is 0.01575Moles.
Then you can calculate concentration :

Total number : 
Here are moles of K+ 0.045/0.075
Of Cl- (0.01575*2)+0.045/0.075
Ca2+ 0.01575/0.075
And the needed answer is definitely : =0.06075

Sorry i dont understand the question can you rephase it?