How many grams of a stock solution that is 87.5 percent h2so4 by mass would be needed to make 275 grams of a 55.0 percent by mass solution? show all of the work needed to solve this problem.

We're diluting the first solution to make the second solution. This means both solutions will contain the same amount of H2SO4 (it's the concentration of it that changes). If you look at it this way, it's easy to find the unknown mass. Call this unknown mass m. m * 0.875 = 275 g * 0.55 --> m = 173 g What I'm saying here is 87.5% of the mass of the first solution needs to be the same as 55% of the mass of the second solution, because you're using the same amount of H2SO4 in both.

Please mark this brainliest! 

D-no effect on the rate

Ch4 is nonpolar and insoluble in water. since all of the hydrogen atoms are evenly spread around the carbon atom even through the c h bond is polar all the poles cancel each other out.