Write a balanced equation for the reaction between hydroiodic acid and lithium hydrosulfite.

HI + LiHSO3 → H2O + SO2 + LiI

Explanation:

Step 1: Data given

hydroiodic acid = HI

lithium hydrosulfite = LiHSO3

Step 2: The unbalanced equation

HI + LiHSO3 → H2O + SO2 + LiI

Step 3: the balanced equation

On the left side we have 2x H (1x in HI and 1x in LiHSO3). On the right side we have 2 moles H (in H2O). The amount of H is balanced.

The amount of moles I , on the left is 1, The amount of moles I on the right is 1 mol. This amount is balanced.

On the left side we have 3x O. (3x in LiHSO3). On the right side we have 3x O, (1x in H2O and 2x in SO2). The amount of O is balanced.

HI + LiHSO3 → H2O + SO2 + LiI

what are the statements