Why is the hybridization of [cr(h2o)6]3+ d2sp3 and not sp3d2?

A inner d orbital complex must be proposed.

Explanation:

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It is seen that in this complex the total charge is +3 as long as the is neutral. Therefore, its electron configuration is:

It means that it has three electrons on 3d sublevel zero on 4s and zero on 4p. Thus, the hybridization comes up from the  fact we've got to complete the hollow spaces (six as there are six waters) into a whole "inner d orbital complex" that is:

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c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current

2b2t

explanation:

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