Review the equation below. 2kclo3 2kcl + 3o2 how many moles of oxygen are produced when 2 mol of potassium chlorate (kclo3) decompose? 1 2 3 6

             3 mol of O₂

The Balance chemical equation is as follow,

                                2 KClO₃    →    2 KCl  +  3 O₂

According to this equation on decomposition 2 moles of Potassium chlorate (KClO₃) produces 2 moles of Poatassium chloride (KCl) and 3 moles of oxygen gas (O₂).

Therefore, when,

                     2 moles of KClO₃ produces  =  3 moles of O₂

So,

                  2 moles of KClO₃ will produce  =  X moles of O₂

Solving for X,

                     X =  (2 mol × 3 mol) ÷ 2 mol

                    X  =  3 mol of O₂

Using above method you can calculate any amount of O₂ or KCl produced by decomposing any amount of KClO₃.

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

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