Chemistry, 01.09.2019 11:30 lottie2306

Acandle is placed on one pan of a balance, and an equal weight is placed on the other pan. what would happen if you lit up the candle and waited for a while?

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Answer from: nick974

The side of the balance on which the candle rests would begin to move upwards.

This is because as the candle burns, it utilizes its wick as fuel, which is transformed into ash and gases. The gases will be lost to the atmosphere, and their mass will no longer be included in the mass of the candle. This would mean that the mass of the candle decreases, and that side of the pan moves upwards.

Answer from: gl648809

The side of candle moves upward due to decrease its weight.

If we lit up the candle and waited for a while than the side of the candle goes upward and the weight on the other side moves downward because the burning of candle decreases its weight.This leads to imbalance of the weight and the other side goes downward.If we do not lit the candle than there is no movement of candle occurs so we can conclude that the side of candle moves upward due to decrease its weight.

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Answer from: Quest

257 grams h2o i think

Answer from: Quest

answer : (a) volume of the gas = 8.67 × $10^{-3}$ l

(b) second virial coefficient b = -1.21226 l/mole

solution : given, t = 300k

p = 20atm

z = 0.86

n = 8.2 mmoles = 8.2 × $10^{-3}$ moles

r = 0.082 l atm/k/mol

find, (a) volume of gas and (b) second virial coefficient b at 300k.

formula used : $z=\frac{pv}{nrt}$

and $z=1+\frac{b}{v}$

(a) $z=\frac{pv}{nrt}$

$v=\frac{znrt}{p}$

= $\frac{0.86\times 8.2\times[tex]10^{-3}$ \times 0.082\times 300}{20}[/tex]

= 8.67 × $10^{-3}$ l

(b) $z=1+\frac{b}{v}$

$b=(z-1)v$

= (0.00867-1) × 8.659

= - 8.5839 l/mole

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Acandle is placed on one pan of a balance, and an equal weight is placed on the other pan. what woul...

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