2. how many grams of water can be heated from 20.0 oc to 75oc using 12500.0 joules?

Specific heat capacity is the amount of energy that required to increase the temperature 1kg of substance by . The 54.1 g of water can be heated from  to using 12500 J.

Specific Heat Capacity:

It is the amount of energy that required to increase the temperature 1kg of substance by .

The specific heat formula,

Where,

Q - Energy absorbed = 12500 J

m - mass(grams) = ?

c -  specific heat = 4,200 J/ kg/

-  change in temperature in kelvin = 75 -20 =

Put the values is the formula,

Solve the equation for m

m = 0.0541 kg = 54.1 g

Hence, we can conclude that the 54.1 g of water can be heated from  to using 12500 J.

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The mass of the water that can be heated from 20 °C  to 75 °C  using 12500.0 J is 54.32 g

We'll begin by calculating the change in the temperature of the water. This can be obtained as follow:

Initial temperature (T₁) = 20 °C

Final temperature (T₂) = 75 °C

ΔT = T₂ – T₁

ΔT = 75 – 20

Change in temperature (ΔT) = 55 °C

Heat (Q) = 12500.0 J

Specific heat capacity of water (C) = 4.184 J/gºC

12500 = M × 4.184 × 55

12500 = M × 230.12

Divide both side by 230.12

M = 12500 / 230.12

Thus, the mass of the water is 54.32 g

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