a chemist produces 460 mL of oxygen gas at -43 C and constant pressure. to what celsius temperature must the oxygen be warmed in order for it to have a volume of 600 mL

27 °C

Explanation:

Applying,

V/T = V'/T' Equation 2

Where V = Initial volume of oxygen, T = Initial temperature, V' = Final volume of oxygen, T' = Final temperature.

Make T' the subject of the equation

T' = V'T/V Equation 2

Form the question,

Given: V' = 600 mL, V = 460 mL, T = -43°C = (-43+273) = 230K

Substitute these values into equation 2

T' = (600×230)/460

T' = 300 K

T' = (300-273) °C

T' = 27 °C

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