Complete the following chemical formula and determine the final molarity of NaCl: __ BaCl2(aq) + __ Na2SO4(aq) --> +

You react 45g BaCl2 with an excess of Na2SO4 in 250mL of water. Find the molarity of NaCl produced.
A. 0.25
B. 0.58
C. 1.72
D. 3.82

[NaCl] = 1.72 M

Explanation:

First of all, we balance the equation:

BaCl₂ + Na₂SO₄ →  2NaCl + BaSO₄

We convert mass of barium chloride to moles

45 g . 1mol / 208.23g = 0.216 moles

Ratio is 1:2. This means, that our moles of reactant may produce the double of moles, of product.

0.216 . 2 = 0.432 moles of NaCl are been produced.

Molarity is mol/L. We convert volume of water from mL to L

250 mL . 1L /1000 mL = 0.250 L

[NaCl] = 0.432 mol/0.250L = 1.72 M

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )