Chemistry, 29.05.2021 08:50 Binger4115

5. Determine if a precipitation reaction occurs between aqueous silver nitrate and aqueous calcium chloride. If a precipitation reaction takes place, write a balanced chemical equation, total ionic equation and net ionic
equation for the reaction. Identify any spectator ions.
a. Balanced chemical equation: (3 marks)
b. Total ionic equation: (2 marks)
C. Net ionic equation: (1 mark)
d. Spectator ions: (1 mark)

Answers: 3

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Answer from: doggosbepis

See Explanation

Explanation:

a) In writing the balanced chemical reaction equation, the number of atoms of each element on the right hand side must be the same as the number of atoms of each element on the left hand side. The balanced reaction equation is;

2AgNO3(aq) + CaCl2(aq) > 2AgCl(s) + Ca(NO3)2(aq)

b) The total ionic equation shows all the ions present in the reaction system as follows;

2Ag^+(aq) + 2NO3^-(aq) + Ca^2+(aq) + 2Cl^-(aq) >2AgCl(s) + Ca^2+(aq) + 2NO3^-(aq)

c) The net ionic equation shows the ions that really participated in the reaction;

2Ag^+(aq) + 2Cl^-(aq) >2AgCl(s)

d) The spectator ions didn't undergo any change from left to right in the reaction equation. They include;

NO3^-(aq) and Ca^2+(aq)

Answer from: Quest

here we have to get the change of moles on decrease the volume of the reaction in gas phase.

the per the given options it will decrease by (d) 11-50%

we know, on decreasing the volume of the gas phase reaction the reaction moves to the product side.

the reaction: so₂cl₂ (g) = so₂ (g) + cl₂ (g) total

the moles at equilibrium: 1 - α α α = 1+α

concentrations: 1 - α α α = 1 + α

(concentration = moles/volume, as volume is 1 l)

(where α is the degree of dissociation)

now the dissociation constant in terms of concentration is :

$k_{c}$ = $\frac{[so2cl2] x [cl2]}{[so2cl2]}$

or, $\frac{\alpha ^{2} }{(1-\alpha)v }$

or, $k_{c}$ = $\frac{\alpha ^{2} }{(1-\alpha) }$ (at v = 1l)

the reaction: so₂cl₂ (g) = so₂ (g) + cl₂ (g) total

the moles at equilibrium: 1 - α α α = 1+α

concentrations: (1 - α)/0.5 α/0.5 α/0.5 = (1 + α)/0.5

thus, the dissociation constant in terms of concentration is :

$\frac{[so2cl2] x [cl2]}{[so2cl2]}$

or, $\frac{\alpha ^{2} }{(1-\alpha)0.5 }$

$\frac{\alpha ^{2} }{(1-\alpha) }$ = $\frac{\alpha ^{2} }{(1-\alpha) 0.5}$

so, the change of 1 : 1/0.5

or, 1: 2

thus it will decrease by 50%.

or, as per the given options it will decrease by 11-50%

Answer from: Quest

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