What is the concentration of a solution made by combining 52 grams of NaCH3COO with 150 mL of water?

The concentration of a solution made by combining 52 grams of   with 150 mL of water is 4.22 M.

Explanation:

Given: Mass = 52 grams

Volume = 150 mL (1 mL = 0.001 L) = 0.150 L

Molarity is the number of moles of a substance present in liter of a solution.

And, moles is the mass of a substance divided by its molar mass.

Hence, moles of (molar mass = 82.034 g/mol) is as follows.

Therefore, concentration of given solution is as follows.

Thus, we can conclude that the concentration of a solution made by combining 52 grams of   with 150 mL of water is 4.22 M.

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !