Calculate the number of moles of NaOH in an aqueous solution of 36 cm3 of 0.1 mol dm−3.

0.0036 moles of NaOH are present

Explanation:

A solution of 0.1mol/dm³ contains 0.1 moles of solute (In this case, NaOH), per 1 dm³ of solution.

36cm³ are in dm³ (1000cm³ / 1dm³):

36cm³ * (1dm³/1000cm³) = 0.036dm³

The moles are:

0.036dm³ * (0.1mol/dm³) = 0.0036 moles of NaOH are present

it is b that is the answer.

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