A reaction has a rate constant of 1.28×10−4 s−1s−1 at 29 ∘C ∘C and 0.227 s−1s−1 at 79 ∘C ∘C . EaEa= 132 kJ/molkJ/mol

What is the value of the rate constant at 16 ∘C ∘C ?

Express your answer in units of inverse seconds.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

the answer is option a.