Based on the equation, how many grams of Br2 are required to react completely with 36.2 grams of AlCl3? 2AlCl3 + 3Br2 → 2AlBr3 + 3Cl2 (5 points) a) 65.2 grams
b) 69.8 grams
c) 72.1 grams
d) 76.5 grams

Consider the reaction: 2al(s) + fe2o3(s) → al2o3(s) + 2fe(s) the δhf for fe2o3(s) = -824.3 kj/mole. the δhf for al2o3(s) = -1675.7 kj/mole. finish the equation. δhrxn = [(1)( kj/mole) + (2)( kj/mole)] - [(1)( kj/mole) + (2) ( kj/mole)]