Write down the products for this reaction c6H14+O2>

C6H14 + O2 >CO2 +H20

the balanced equation is :

2C6H14 + 19O2 → 12CO2 + 14H2O

Explanation:

in other ords this equation can be written as:

hexane +oxygen > carbon dioxide + water

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The combustion of hexane (C6H14) is represented in the balanced equation : 2 C6H14 + 19 O --- 12 CO2 + 14 H2O MM hexane 86.18 g/mole, O2 32 g/mole, CO2 44 g/ mole, H2O 18 g/mole A. If 45 g of hexane is reacted and 45 g of water is recovered.

Explanation:

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

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