What change would shift the equilibrium system to the left? A(g) + B(s) + Energy ⇌ 3C(g) (3 points)
Adding more of gas C to the system
Heating the system
Increasing the volume
Removing some of gas C from the system

A.) Adding more of gas C to the system

Explanation:

A.) is correct because the reaction wants to keep the same amount of reactants and products that sustain equilibrium. If you are increasing the amount of gas C, this will push the reaction to make more of the reactants to restore the balance.

B.) is incorrect because heat is a form of energy. As previously stated, when you add more material to the reactants side, the equilibrium shifts to the product side to restore equilibrium.

C.) is incorrect because when the volume is increased, the equilibrium will shift to the side with the greater amount of moles of gas. There is 1 mole of gas on the reactant side (from A (g)) and 3 moles of gas on the products side (from 3 C (g)). Therefore, the reaction will shift to the product side.

D.) is incorrect because if the material on the product side is decreasing, the equilibrium will want to make up that difference by shifting to the product side.

Remember,

reactants ---> products

well off of my head we know that the perfume bottle is most likely opened, or broken. i can also tell it is moving at low and high concentration because it is covering the other side of the room. what we can obtain from this information is it explains why the odor can be detected at the other side of the room.

8

explanation:

each principal energy level above the first contains one s orbital and three p orbitals. a set of three p orbitals, called the p sublevel, can hold a maximum of six electrons. therefore, the second level can contain a maximum of eight electrons - that is, two in the s orbital and 6 in the three p orbitals.

mark brainliest and have a great day!