Calculate the moles and the mass of solute in 250.0 ml of 6.00 m naoh

Explanation:

As molarity is the number of moles present in liter of solution. So, convert given volume into liter as follows.

                  (as 1 L = 1000 ml)

               = 0.25 L

Therefore, number of moles of solute present will be calculated as follows.

       Molarity =

                      6.00 M =

                    no. of moles = 1.5 mol

Hence, number of moles of solute in 250.0 ml of 6.00 M NaOH is 1.5 mol.

Now, calculate the mass of solute as follows.

           No. of moles =

                    1.5 mol =        

                 mass = 59.98 g

Thus, we can conclude that mass of solute in 250.0 ml of 6.00 M NaOH is 59.98 g.

c. 75.7

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