What is the value for ∆soreaction for the following reaction, given the standard entropy values? c6h12o6(s) + 6o2(g) 6co2(g) + 6h2o(l) a+131 j/k b -131 j/k c +262 j/k d -262 j/k e +417 j/k

Most likely a is the answer - because  you generate   38 atp's but also consume an atp.   each atp gives approx. less than 4 kcal so probably a is the closest answer.

Spontaneity tell us the direction of the reaction, but not how fast it goes. gibbs free energy brings together enthalpy, entropy and temperature in one easy formula. g = h - ts. and, finally the sign of delta g is always negative for a spontaneous reaction.