Calculate the moles of carbon dioxide that are released when 44.7 g of calcium carbonate (molar mass = 100.0 g/mol) is heated (assuming that the reaction goes to completion). give your answer to three significant figures.

0.447 moles of CO2 are released. Calcium carbonate has a formula of CaCO3 and when heated breaks down into calcium oxide (CaO) and carbon dioxide (CO2). So the balanced reaction is CaCO3 ==> CaO + CO2 So each mole of CaCO3 will produce 1 mole of CO2. So let's calculate how many moles of CaCO3 we have. 44.7 g / 100.0 g/mol = 0.447 mol And since we only have 3 significant figures, the answer already has the correct number of significant figures.

Wow that a lot of text for my tiny so i no wanna answer