You are trying to determine the volume of the balloon needed to match the density of the air in the lab. you know that if you can get the balloon's density below this value, it will float. you measure both the temperature in the room as well as the mass of the balloon you will use and find they are 18.0°c and 0.577 grams, respectively. what volume of balloon will generate a density equal to that of the air around it? (hint: use the relationship you calculated above to determine the air density at the temperature given) balloon volume needed = equation from problem 1 : y = -0.0043x + 1.2874

Answer is: volume of balloon is 476,85 cm³.
density of air: d(air) = -0,0043 · 18,0°C + 1,2874.
d(air) = 1,21 kg/m³ = 1,21 · 10³/ 10⁶ = 0,00121 g/cm³.
m(balloon) = 0,577 g.
d(balloon) = d(air).
d(balloon) = m(balloon) ÷ V(balloon).
V(balloon) = m(balloon) ÷ d(balloon)
V(balloon) = 0,577 g ÷ 0,00121 g/cm³.
V(balloon) = 476,85 cm³.

For cyclohexane compounds drawn in a chair conformation:   -axial bonds are vertical  -equatorial bonds are parallel to two bonds within the ring.  thus, as i assume the chair conformation is drawn:   -the x group is in an axial position, as are the five other vertical bonds.  -three axial bonds are on the top face of the ring  -the other three axial bonds are on the bottom face  the position of the second substituent on each ring carbon is equatorial.  gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other.  drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1.  click this link and watch some academic videos that may you more understand the topic 

Idon’t know sorry i don’t know the answer i’m s sorry