How does the rate of effusion of sulfur dioxide, so2, compare to that of helium (he)? (note: the molar masses are so2 = 64 g/mol; he = 4.0 g/

Answer : The rate of effusion of helium gas is four times of the rate of effusion of sulfur dioxide gas.

Solution : Given,

Molar mass of sulfur dioxide gas = 64 g/mole

Molar mass of helium gas = 4.0 g/mole

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

or,

where,

= rate of effusion of sulfur dioxide gas

= rate of effusion of helium gas

= molar mass of sulfur dioxide gas

= molar mass of helium gas

Now put all the given values in the above formula, we get

Therefore, from this we conclude that, the rate of effusion of helium gas is four times of the rate of effusion of sulfur dioxide gas.