When 711 j of heat is added to a 41.1 g of an unknown metal, the temperature of the metal increases from 22oc to 94oc. calculate the specific heat of this metal

The   specific  heat  capacity  of   the  metal  is   calculated  as follows

  heat energy =  Mc delta  T
heat  energy (Q) = (711 j  )
m=mass    (41.1 g)
c=  specific  heat  capacity  =?
delta  t =  change  in  temperature(  94 -22=72)

c=  Q/m  delta  T
  c=711 j  /  (41.1 g  x72)  =  0.240  j/g /k

They can measure  the amount of energy gained or lost

The answers is a nuclear changes