3.26 LAB: Leap Year A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 the output is: 1712 - leap year

year = int(input("Enter a year: "))

if (year % 4) == 0:

  if (year % 100) == 0:

      if (year % 400) == 0:

          print(str(year) + " - leap year")

      else:

          print(str(year) +" - not a leap year")

  else:

      print(str(year) + " - leap year")

else:

  print(str(year) + "- not a leap year")

Explanation:

*The code is in Python.

Ask the user to enter a year

Check if the year mod 4 is 0 or not. If it is not 0, then the year is not a leap year. If it is 0 and if the year mod 100 is not 0, then the year is a leap year. If the year mod 100 is 0, also check if the year mod 400 is 0 or not. If it is 0, then the year is a leap year. Otherwise, the year is not a leap year.

i_year=int(input(""))

#check leap year

if((i_year % 4 == 0 and i_year % 100 != 0) or (i_year % 400 == 0)):

  print("{} is a leap year.".format(i_year))

else:

  print("{} is not a leap year.".format(i_year))

Explanation:

answer is c. complication