The position of a particle moving along a straight line is defined by the relation. s = t^3 – 6t^2 – 15t + 40, where s is expressed in feet and t in seconds. determine: (a) s when t = 3 seconds.(b) v when t = 5 seconds. (c) a when t = 4 seconds.(d) the time when the velocity is equal to zero. what is important about this information?

1) s(3) = -32 feet.

2)v(5) = 3 feet/sec

3)a(4) = 12

4) Velocity becomes zero at t = 5 seconds

Explanation:

Given that position as a function of time is

Now by definition of velocity we have

Now by definition of acceleration we have

Applying values of time in corresponding equations we get

1) s(3)=

2)v(5)=

3)a(4)=

4)To obatin the time at which velocity is zero equate the velocity function with zero we get

Thus the correct time is 5 seconds at which velocity becomes zero.

answer:

50 vo; ts

explanation: