A hollow stainless steel shaft with an outside diameter of 42 mm and a wall thickness of 4 mm has an allowable shear stress of 100 MPa. Determine the maximum torque T that may be applied to the shaft.

669495.83Nmm

Explanation:

The equation that relates Torque(T), Maximun shear stress (**), inside and outside diameters of the stainless steel shaft (di and do) is given by

T=pi×**/16 ×((do⁴-di⁴/do))

Where pi=3.142

do= 42mm

di=42-2thickness

di=42-2×4

di=36mm

T=3.142×100/16 ×((42⁴-36⁴/42))

T=669495.83Nmm

answer:

a

explanation:

answer:

clock

explanation:

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