Steam at 5 MPa and 400 C enters a nozzle steadily with a velocity of 80 m/s, and it leavesat 2 MPa and 300 C. The inlet area of the nozzle is 50 cm2, and heat is being lost at a rateof 120 kJ/s. Determine the following: a) the mass flow rateof the steam.
b) the exit velocity of the steam.
c) the exitarea of the nozzle.

a) the mass flow rate of the steam is  

b) the exit velocity of the steam  is

c) the exit area of the nozzle is   = 0.0015435 m²

Explanation:

Given that:

A steam with 5 MPa and 400° C enters a nozzle steadily

So;

Inlet:

5 MPa

= 400° C

Velocity V = 80 m/s

Exit:

2 MPa

= 300° C

From the properties of steam tables  at 5 MPa and = 400° C we obtain the following properties for enthalpy h and the speed v

From the properties of steam tables  at 2 MPa and = 300° C we obtain the following properties for enthalpy h and the speed v

Inlet Area of the nozzle = 50 cm²

Heat lost Q = 120 kJ/s

We are to determine the following:

a) the mass flow rate of the steam.

From the system in a steady flow state;

Thus

b) the exit velocity of the steam.

Using Energy Balance equation:

In a steady flow process;

c) the exit area of the nozzle.

The exit of the nozzle can be determined by using the expression:

making the subject of the formula ; we have:

= 0.0015435 m²

explanation:

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answer:

the answer is d

explanation: