the diodes were ideal:a. What dc output voltage should the half-wave rectifier produce?b. What dc output voltage should the bridge rectifier produce?2.What is the peak reverse voltage impressed across the diode: a. In the half-wave rectifier with capacitor in parallel with the load resistor?b. In the bridge rectifier with capacitor in parallel with the load resist

1) a)  i)  V =  

       ii) V =

  b) i)   V =

     ii)     V =

2) a) 2Vpeak

   b) P/ V =

Explanation:

1) If the diodes were ideal

a)  The dc output voltage the half-wave rectifier should produce

 ii ) without a capacitor

     V =  

  ii) with a capacitor filter

    V =      ;   where

    V =

b) The  dc output voltage the bridge rectifier should  produce

  i) without a capacitor

     V =

 ii ) with a capacitor

    V =

2) a) peak reverse voltage in the half-wave rectifier with capacitor in parallel with the load resistor

during -ve half cycle

 P/V =

 Voltage across capacitor = Vc = Vpeak

Therefor the PIV for a half-wave rectifier with capacitor in parallel

= 2 * Vpeak = 2Vpeak

 b) Peak reverse voltage in the bridge rectifier with capacitor in parallel with the load resist

P/ V =

answer:

a

explanation:

answer: chicken nuggets.

explanation: