Lf is such that 4y - 7 <3y and 3y -5y + 8. find the range of the values that satisfies both inequalities.

Take 3y to the other side = y-7<0 and take - 7 to the other side y<7

Second one has to inequalities present so it be more than 0 or less than 0. So way the same steps to find y on its own e.g. y>3 all the numbers between 3 and 7 which is 4,5,6 and so you draw circle over 3 and 7 and you connect the lines however if the inequality symbol is less or equal to or more than equal to shade the circle to show the inequality if i tells you to draw it on a number line.

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x=4, y=4

step-by-step explanation:

y=2x-4;

x+2y=12

we can use substitution since the first equation is solved for y

where ever you see y in the second equation, replace it with 2x-4

x + 2(2x-4) = 12

distribute the 2

x+4x-8 = 12

combine like terms

5x-8=12

add 8 to each side

5x-8+8=12+8

5x=20

divide by 5

5x/5 = 20/5

x =4

we still need to solve for y

y = 2x-4

we know x =4

y = 2(4) -4

y = 8-4

y=4