Choose the equation of a line in standard form that satisfies the given conditions. perpendicular to 4x + y = 8 through (4, 3) a. x − 4y = −8 b. x + 4y = 16 c. 4x − y = 11 d. 4x + y = 19

We have that
Choose the equation of a line in standard form that satisfies the given conditions. perpendicular to 4x + y = 8 through (4, 3)

4x + y = 8-----> y=-4x+8-----> the  slope m is -4

we know that
 if two lines are perpendicular
then
m1*m2=-1
m1=-4
so
m2=1/4

with m=1/4 and point (4,3)
find the equation of the line
y=mx+b
3=(1/4)*4+b-----> 3=1+b-----> b=2
y=(1/4)*x+2------> (1/4)*x-y=-2-----> multiply by 4----> x-4y=-8

the answer is the option
A. x − 4y = −8

Ithink ghe answer to this question is b just trying to others