Find the ninth term of the sequence sqrt 5, sqrt 10, ^2sqrt 5 sqrt 20 20 sqrt 5 16 sqrt 5 48 sqrt 5

The rule of geometric sequence is   ⇒⇒⇒ a * r^(n-1)
Where a is the first term and  r is the common ratio
for the given sequence  √5 , √10 , 2√5 ,
a = √5
r = √10 / √5 = √2
The ninth term = √5 * (√2)^(9-1) = √5 * (√2)⁸ = 16 √5

the correct answer is the third option 16√5

The answer is -pie over 2