Write an equation for the nth term of the arithmetic sequence. then find a50. 3, 9, 15, 21, . . an= 6n-3 a50= ?

an = 3 + 6 (n-1)

the 50th term is 297

Step-by-step explanation:

We know that the formula used to find the nth term of a sequence is given by:

an = a₁ + d(n - 1)

where an is the nth term, a₁ is the first term and d is the common difference.

In this case a₁ = 3, d = 6 and n =50.

Therefore:

an = 3 + 6(49) = 3 + 294 = 297.

answer: 370

step-by-step explanation:

remember use pemdas! there are no parentheses or exponents so lets move onto the first part of the equation: multiplication and division. first, lets break the first part of the equation up into something easier using the distributive property. 28 * 12= (20 *12) + (8*12) you know that 20*12 is 240 and 8*12 is 96. add them and you get 336. then, lets solve the last part of the equation (the last part of pemdas is addition and subtraction). 336 plus 34 is 370. hope this !