Is there a series of rigid transformations that could map δqrs to δabc? if so, which transformations could be used?

Yes, ΔQRS  can be translate to so that Q is mapped to point A, then reflect across line containing QS.

Step-by-step explanation:

In the given picture , we have two triangles ΔQRS and ΔABC in which we have ,

QR=AB = 16 cm

RS=BC= 24 cm

∠R=∠B=90°

By SAS postulate of congruence , ΔQRS ≅ ΔABC.

There are three main rigid transformations which produces congruent images.

1) Translations 2) Rotation 3) Reflection

When we look the given picture, it can be seen that ΔABC is the mirror image of ΔQRS.

But line QS is at some distance from AC , so we first translate ΔQRS to so that Q is mapped to point A, then reflect across line containing QS.

good luck on your studies! : )

david edward.

45.36 feet per second

step-by-step explanation:

tyrone travels 30 miles in 58.2 minutes.  

1 mile = 5280 feet; this means he travels

30(5280) = 158400 feet in 58.2 minutes.

1 minute = 60 seconds; this means he travels 158400 feet in

58.2(60) = 3492 seconds.

this gives us the unit rate of

158400/3492 = 45.36 feet per second.