Multiple ! to approach the runway, a pilot of a small plane must begin a 10°   descent starting from a height of 1983 feet above the ground. to the nearest tenth of a mile, how many miles from the runway is the airplane at the start of this approach? question 3 options: 11,419.6 mi 2.2 mi 0.4 mi 2.1 mi

Option B. 2.2 miles.

Step-by-step explanation:

A pilot of a small plane must begin a 10° descent starting from a height of 1983 feet above the ground that is AB is the height of plane above the ground, AB= 1983 feet. and A is the point from where the pilot starts descent.

thus, ∠ACB = ∠DAC = 10°

We have to find the distance between the runway and the airplane where it start this approach that is we have to find length AC( in miles).

Let AC = x

Applying trigonometric ratio,

Put the values into the formula

sin 10° =

0.1737 =

x =

x= 11419.64

The distance from the runway to the airplane is 11419.64 feet.

As we know 1 mile = 5280 feet

11419.64 feet =

= 2.16 miles ≈ 2.2 miles

Option B. 2.2 mi is the correct answer.

none of these

step-by-step explanation:

23 + 34 add up to 57 so just inform the teacher of this really stupid mistake

choice b

step-by-step explanation:

f(x) = 88x^2 -264x + 300

the line of symmetry of a parabola is defined by

h = -b/2a

where ax^2 +bx+c=0

so

h = - -264/ (2*88)

h = 3/2

so x = 1.5