Solve this dont give stupid answer for

(i)

∠BAD + ∠ABD + ∠ADB = 180 the sum of the angles of a triangle equals 180°

70 + 50 + ∠ADB = 180 substituted given information

∠ADB = 60 subtraction property (subtracted 70 and 50)

∠ABD + ∠BDC = ∠ADC angle addition property

60 + ∠BDC = 80 substituted solved and given information

∠BDC = 20 subtraction property

(ii) SORRY but I'm not sure how to find ∠BCD. If ∠ADC = ∠ABC, then ∠DBC = 30. We already calculated ∠BDC = 20, which means that ∠BCD = 130

(iii)

∠BCA = ∠ADB given as a hint

∠BCA = 60 substituted ∠ADB that was solved in part (i)

(i) = 20, (ii) = 130?, (iii) = 60

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x