Which interval for the graphed function contains the local maximum? [–1, 0] [1, 2] [2, 3] [3, 4]

Local maximum = [3, 4]

Step-by-step explanation:

Step 1: Plot the given points [–1, 0] [1, 2] [2, 3] [3, 4] and draw the graph.

Step 2: Observe the graph, it is a straight line. Which has local minimum and local maximum at the closed interval.

Here with I have attached the graph.

The graphed function at local maximum at [3, 4]

Thank you.

The local maximum value of the function is in the interval of and local maximum value of the function is in the interval of

Further explanation:

Given:

The intervals are and

Explanation:

The given intervals are and

Plot the given points on the graph to obtain the local maximum value and the local minimum value in the given intervals.

The maximum value of the graphed function is 4 at 3.

The minimum value of the function is -1 at 0.

The local maximum value of the function is in the interval of and local maximum value of the function is in the interval of

Kindly refer to the imaged attached.

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Answer details:

Grade: High School

Subject: Mathematics

Chapter: Linear inequality

Keywords: interval, graphed, function, contains, local maximum, maximum, [-1,0], graphed function.

for the points

step-by-step explanation:

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!