Find an equation for the line that passes through the given point and satisfies the given conditions. 11) 11) p = ( 9 , 2 ); perpendicular to v = 4 i + 4 j

You can use the direction vector as the coefficients of x and y for a line through (0, 0) perpendicular to that direction: x + y = 0. (A common factor of 4 can be removed from the coefficients.)

Translating the line up 2 and right 9, so it goes through the given point, we get ...

... (x -9) +(y -2) = 0

or

... x + y = 11

the sum of all the angles in a triangle are equal to 180

so you can add   the 3 given angles together to equal 180:

5y + 2y + 2y = 180

or since all three angles have the same letter, combine the 3 angles to equal 180:

9y = 180

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5