For competition, the cheerleading team, is preparing a dance routine that must last 4 minutes, with a variation of +- 5 seconds. find the least and greatest possible times for the routine in minutes and seconds. find the least and greatest possible times in seconds

Ideal timeline of the dance routine = 4 minutes = 4 × 60 seconds = 240 seconds

Variation allowed in the dance routine timeline = +- 5 seconds

Let the timeline of the dance routine be T

⇒ 240 seconds - 5 seconds < T < 240 seconds + 5 seconds

⇒ 235 seconds < T < 245 seconds

⇒ minutes < T < minutes

⇒ 3.92 minutes < T < 4.08 minutes

So the least possible time of the dance routine can be 3.92 minutes (or 235 seconds) and the greatest possible time of the dance routine can be 4.08 minutes (or 245 seconds)

step-by-step explanation:

no, her answer is not correct.   we square the lengths of all sides and then determine whether the pythagorean theorem holds here:

9² + 15² = 306.   this is not equal to the square of the longest side ( that square being 395.   answer c is correct.