The straight line joining the points a(3,-5) and b(6,k) has a gradient of 4. work out the value of k.

The straight line joining the points A(3,-5) and B(6,k) has a gradient of 4.

Gradient is the slope

So the slope of the line joining the points A(3,-5) and B(6,k) is 4

Slope of line joining two points =

A(3,-5) and B(6,k) are (x1,y1)  and (x2,y2)

slope =

slope =

We know slope =4

Cross multiply  and solve for k

k + 5 = 12

k = 7

The value of k = 7

i think asking google will you get the answer to that question

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!