Consider the diagram and the derivation below. given: in △abc, ad ⊥ bc derive a formula for the area of △abc using angle c. it is given that in △abc, ad ⊥ bc. using the definition of sine with angle c in △acd results in sin(c) = . using the multiplication property of equality to isolate h, the equation becomes bsin(c) = h. knowing that the formula for the area of a triangle is a = bh is and using the side lengths as shown in the diagram, which expression represents the area of △abc? bsin(c) absin(c) cbsin(c) hbsin(c) mark this and return

Step-by-step explanation:

First consider the diagram:

Now, we know that

Now, the area of the triangle ABC is given by,

3=log(n)=2

answer a: product property

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.