Afootball is kicked into the air from the initial height of 3 ft. the height, in feet, of the football above the ground is given by s(t) = -16t^2 + 35t + 3, where t is time in seconds and t is greater than or equal to 0. which is closest to the time when the football will be 20 ft above ground? a. 2.72 sec b. 0.73 sec or 1.46< c. 0.53 sec d. 0.53 sec or 2.72 sec

B

Step-by-step explanation: As you can see, -16t^2 + 35t + 3 is a quadratic equation, where t is the time and s is the height. Since we have the height and we know that 20 is equal to -16t^2 + 35t + 3 we can solve it.

Let's order it: 20 = -16t^2 +35t + 3 -> 16t^2 - 35t - 3 + 20 = 0 -> 16t^2 - 35t + 17 = 0

And we can use the quadratic formula.

t1,2 = 35±√1225-1088 / 32 = 35±√137 / 32

We have t1 = 35 + √137 / 32 = 0,727 which we can approximate to 0,73

t2 = 35 - √137 / 32 = 1,459 which we can approximate to 1,46

Why do we have two solution? Of course, it is a quadratic equation and it has two solution but expecially because one is the time when the ball goes up and one is the time when it goes down.

hi,

3. 12.15, you are correct.

4.2.01, your first digit is correct,

hope this !

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation: