Afootball is punted into the air. its height h, in metres, after t seconds is given by the equation h = ? 4.9t2 + 24.5t +1. how high is the ball after 1 second?

After 1 second, the ball is 30.4 meters high.

Step-by-step explanation:

Hi, to answer this question we simply have to substitute t=1 in the equation given:

h = 4.9t2 + 24.5t +1

Replacing t (seconds) by 1 (second)

h= 4.9 (1) ^2 + 24.5 (1) +1

Solving for h:

h= 4.9 (1) +24.5 +1

h= 30.4 meters

After 1 second, the ball is 30.4 meters high.

Feel free to ask for more if needed or if you did not understand something.

muyb ajo

step-by-step explanation:

jegosu