Find the distance from p to l. line l contains points (-4,2) and (3,-5). point p has coordinates (1,2). a. 55√5 , or appx 2.2 b. 67√7 , or appx 2.3 c. 52√2 , or appx 3.5 d. 103√3 , or appx 5.8

To Find: Distance between point P to line l

Solution: Points lying on line l are suppose A (-4,2) and B (3,-5).

Equation of line passing through (p,q) and (a,b) is given by the equation

 →

Equation of line AB is ,

→

→y -2 = -1× (x +4)

→y -2 = -x -4

→x + y +4-2=0

→ x + y +2=0

Distance between point P (1,2) and line l whose equation is ,x+y+2=0 is given by= =5√2/2=3.535(approx)→Option (C)

→Which is given by the formula ,i.e if a line has equation , Ax + By +c=0 and we have to find the distance from (p,q) is given by =

1 1/5

step-by-step explanation:

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.